72x^2-92=0

Solution for 72x^2-92=0 equation:

72x^2-92=0

a = 72; b = 0; c = -92;
Δ = b2-4ac
Δ = 02-4·72·(-92)
Δ = 26496
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{26496}=\sqrt{576*46}=\sqrt{576}*\sqrt{46}=24\sqrt{46}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-24\sqrt{46}}{2*72}=\frac{0-24\sqrt{46}}{144}
=-\frac{24\sqrt{46}}{144}
=-\frac{\sqrt{46}}{6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+24\sqrt{46}}{2*72}=\frac{0+24\sqrt{46}}{144}
=\frac{24\sqrt{46}}{144}
=\frac{\sqrt{46}}{6}
$